(1)/(2)c+10=(5-7c)/(6)

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Solution for (1)/(2)c+10=(5-7c)/(6) equation: 



(1)/(2)c+10=(5-7c)/(6)

We move all terms to the left:

(1)/(2)c+10-((5-7c)/(6))=0



Domain of the equation: 2c!=0

c!=0/2

c!=0

c∈R



We add all the numbers together, and all the variables

1/2c-((-7c+5)/6)+10=0

We calculate fractions


()/12c^2+(-((-7c+5)*2c)/12c^2+10=0

We calculate fractions

We do not support ecpression: c^4

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