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(1)/(2)x+(3)/(2)(x+1)-(1)/(4)=5
We move all terms to the left:
(1)/(2)x+(3)/(2)(x+1)-(1)/(4)-(5)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 2(x+1)!=0determiningTheFunctionDomain 1/2x+3/2(x+1)-5-1/4=0
x∈R
We calculate fractions
(8xx/(16x^2x+96x/(16x^2x+(-8x^2)/(16x^2x-5=0
We can not solve this equation
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