(1)/(2)x+84=(2)/(3)x

Solution for (1)/(2)x+84=(2)/(3)x equation:

(1)/(2)x+84=(2)/(3)x

We move all terms to the left:

(1)/(2)x+84-((2)/(3)x)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

1/2x-(+2/3x)+84=0

We get rid of parentheses

1/2x-2/3x+84=0

We calculate fractions


3x/6x^2+(-4x)/6x^2+84=0

We multiply all the terms by the denominator


3x+(-4x)+84*6x^2=0

Wy multiply elements

504x^2+3x+(-4x)=0

We get rid of parentheses

504x^2+3x-4x=0

We add all the numbers together, and all the variables

504x^2-1x=0

a = 504; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·504·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*504}=\frac{0}{1008}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*504}=\frac{2}{1008}
=1/504
$