(1)/(2)x-16=-28-(1)/(4)x

Solution for (1)/(2)x-16=-28-(1)/(4)x equation:

(1)/(2)x-16=-28-(1)/(4)x

We move all terms to the left:

(1)/(2)x-16-(-28-(1)/(4)x)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

1/2x-(-1/4x-28)-16=0

We get rid of parentheses

1/2x+1/4x+28-16=0

We calculate fractions


4x/8x^2+2x/8x^2+28-16=0

We add all the numbers together, and all the variables

4x/8x^2+2x/8x^2+12=0

We multiply all the terms by the denominator


4x+2x+12*8x^2=0

We add all the numbers together, and all the variables

6x+12*8x^2=0

Wy multiply elements

96x^2+6x=0

a = 96; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·96·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*96}=\frac{-12}{192}
=-1/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*96}=\frac{0}{192}
=0
$