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(1)/(2)y+(3)/(4)y=7+(2)/(3)y
We move all terms to the left:
(1)/(2)y+(3)/(4)y-(7+(2)/(3)y)=0
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
Domain of the equation: 4y!=0
y!=0/4
y!=0
y∈R
Domain of the equation: 3y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
1/2y+3/4y-(2/3y+7)=0
We get rid of parentheses
1/2y+3/4y-2/3y-7=0
We calculate fractions
We do not support eypression: y^3
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