(1)/(3)(21-9n)=4(2n-7)-9

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Solution for (1)/(3)(21-9n)=4(2n-7)-9 equation: 



(1)/(3)(21-9n)=4(2n-7)-9

We move all terms to the left:

(1)/(3)(21-9n)-(4(2n-7)-9)=0



Domain of the equation: 3(21-9n)!=0

n∈R



We add all the numbers together, and all the variables

1/3(-9n+21)-(4(2n-7)-9)=0

We multiply all the terms by the denominator


-((4(2n-7)-9))*3(-9n+21)+1=0



We calculate terms in parentheses: -((4(2n-7)-9))*3(-9n+21), so:

(4(2n-7)-9))*3(-9n+21

We add all the numbers together, and all the variables

-9n+(4(2n-7)-9))*3(+21

Back to the equation:

-(-9n+(4(2n-7)-9))*3(+21)



We add all the numbers together, and all the variables

-(-9n+(4(2n-7)-9))*321+1=0

We move all terms containing n to the left, all other terms to the right

-(-9n+(4(2n-7)-9))*321=-1

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