(1)/(3)(2x+8)=(1)/(5)(3x-5)

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Solution for (1)/(3)(2x+8)=(1)/(5)(3x-5) equation: 



(1)/(3)(2x+8)=(1)/(5)(3x-5)

We move all terms to the left:

(1)/(3)(2x+8)-((1)/(5)(3x-5))=0



Domain of the equation: 3(2x+8)!=0

x∈R





Domain of the equation: 5(3x-5))!=0

x∈R



We calculate fractions


(5x3/(3(2x+8)*5(3x-5)))+(-3x2/(3(2x+8)*5(3x-5)))=0



We calculate terms in parentheses: +(5x3/(3(2x+8)*5(3x-5))), so:

5x3/(3(2x+8)*5(3x-5))

We multiply all the terms by the denominator


5x3

We add all the numbers together, and all the variables

5x^3

We do not support expression: x^3

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