(1)/(3)(x+6)=(2)/(3)(x-9)

Solution for (1)/(3)(x+6)=(2)/(3)(x-9) equation:

(1)/(3)(x+6)=(2)/(3)(x-9)

We move all terms to the left:

(1)/(3)(x+6)-((2)/(3)(x-9))=0


Domain of the equation: 3(x+6)!=0

x∈R



Domain of the equation: 3(x-9))!=0

x∈R


We calculate fractions


(3xx/(3(x+6)*3(x-9)))+(-6xx/(3(x+6)*3(x-9)))=0


We calculate terms in parentheses: +(3xx/(3(x+6)*3(x-9))), so:

3xx/(3(x+6)*3(x-9))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)



We calculate terms in parentheses: +(-6xx/(3(x+6)*3(x-9))), so:

-6xx/(3(x+6)*3(x-9))

We multiply all the terms by the denominator


-6xx

Back to the equation:

+(-6xx)


We get rid of parentheses

3xx-6xx=0