(1)/(3)(x-2)+(3)/(5)(x+9)=(14)/(15)

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Solution for (1)/(3)(x-2)+(3)/(5)(x+9)=(14)/(15) equation: 



(1)/(3)(x-2)+(3)/(5)(x+9)=(14)/(15)

We move all terms to the left:

(1)/(3)(x-2)+(3)/(5)(x+9)-((14)/(15))=0



Domain of the equation: 3(x-2)!=0

x∈R





Domain of the equation: 5(x+9)!=0

x∈R



We add all the numbers together, and all the variables

1/3(x-2)+3/5(x+9)-(+14/15)=0

We get rid of parentheses

1/3(x-2)+3/5(x+9)-14/15=0

We calculate fractions


(75xx/(3(x-2)*5(x+9)*15)+(135xx/(3(x-2)*5(x+9)*15)+(-210x^2x/(3(x-2)*5(x+9)*15)=0



We calculate terms in parentheses: +(75xx/(3(x-2)*5(x+9)*15)+(135xx/(3(x-2)*5(x+9)*15)+(-210x^2x/(3(x-2)*5(x+9)*15), so:

75xx/(3(x-2)*5(x+9)*15)+(135xx/(3(x-2)*5(x+9)*15)+(-210x^2x/(3(x-2)*5(x+9)*15

We can not solve this equation

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