(1)/(3)b-2=5

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Solution for (1)/(3)b-2=5 equation: 



(1)/(3)b-2=5

We move all terms to the left:

(1)/(3)b-2-(5)=0



Domain of the equation: 3b!=0

b!=0/3

b!=0

b∈R



We add all the numbers together, and all the variables

1/3b-7=0

We multiply all the terms by the denominator


-7*3b+1=0

Wy multiply elements

-21b+1=0

We move all terms containing b to the left, all other terms to the right

-21b=-1

b=-1/-21

b=1/21

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