(1)/(3)m=24

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Solution for (1)/(3)m=24 equation: 



(1)/(3)m=24

We move all terms to the left:

(1)/(3)m-(24)=0



Domain of the equation: 3m!=0

m!=0/3

m!=0

m∈R



We multiply all the terms by the denominator


-24*3m+1=0

Wy multiply elements

-72m+1=0

We move all terms containing m to the left, all other terms to the right

-72m=-1

m=-1/-72

m=1/72

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