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(1)/(4)c+2=(3)/(4)
We move all terms to the left:
(1)/(4)c+2-((3)/(4))=0
Domain of the equation: 4c!=0We add all the numbers together, and all the variables
c!=0/4
c!=0
c∈R
1/4c+2-(+3/4)=0
We get rid of parentheses
1/4c+2-3/4=0
We calculate fractions
2!=0
There is no solution for this equation
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