(1)/(5)(2x-1)=(1)/(3)(x+4)

Solution for (1)/(5)(2x-1)=(1)/(3)(x+4) equation:

(1)/(5)(2x-1)=(1)/(3)(x+4)

We move all terms to the left:

(1)/(5)(2x-1)-((1)/(3)(x+4))=0


Domain of the equation: 5(2x-1)!=0

x∈R



Domain of the equation: 3(x+4))!=0

x∈R


We calculate fractions


(3xx/(5(2x-1)*3(x+4)))+(-5x2/(5(2x-1)*3(x+4)))=0


We calculate terms in parentheses: +(3xx/(5(2x-1)*3(x+4))), so:

3xx/(5(2x-1)*3(x+4))

We multiply all the terms by the denominator


3xx

Back to the equation:

+(3xx)



We calculate terms in parentheses: +(-5x2/(5(2x-1)*3(x+4))), so:

-5x2/(5(2x-1)*3(x+4))

We multiply all the terms by the denominator


-5x2

We add all the numbers together, and all the variables

-5x^2

Back to the equation:

+(-5x^2)


We get rid of parentheses

-5x^2+3xx=0