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(1)/(5)(3x-1)=(1)/(3)(x-1)
We move all terms to the left:
(1)/(5)(3x-1)-((1)/(3)(x-1))=0
Domain of the equation: 5(3x-1)!=0
x∈R
Domain of the equation: 3(x-1))!=0We calculate fractions
x∈R
(3xx/(5(3x-1)*3(x-1)))+(-5x3/(5(3x-1)*3(x-1)))=0
We calculate terms in parentheses: +(3xx/(5(3x-1)*3(x-1))), so:
3xx/(5(3x-1)*3(x-1))
We multiply all the terms by the denominator
3xx
Back to the equation:
+(3xx)
We calculate terms in parentheses: +(-5x3/(5(3x-1)*3(x-1))), so:
-5x3/(5(3x-1)*3(x-1))
We multiply all the terms by the denominator
-5x3
We add all the numbers together, and all the variables
-5x^3
We do not support expression: x^3
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