(1)/(5p2)*(5p3-35p2)/(9p-36)

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Solution for (1)/(5p2)*(5p3-35p2)/(9p-36) equation:


D( p )

9*p-36 = 0

5*p^2 = 0

9*p-36 = 0

9*p-36 = 0

9*p-36 = 0 // + 36

9*p = 36 // : 9

p = 36/9

p = 4

5*p^2 = 0

5*p^2 = 0

5*p^2 = 0 // : 5

p^2 = 0

p = 0

p in (-oo:0) U (0:4) U (4:+oo)

((1/(5*p^2))*(5*p^3-(35*p^2)))/(9*p-36) = 0

((1/(5*p^2))*(5*p^3-35*p^2))/(9*p-36) = 0

(1/5*p^-2*(5*p^3-35*p^2))/(9*p-36) = 0

5*p^3-35*p^2 = 0

5*p^2*(p-7) = 0

p-7 = 0 // + 7

p = 7

5*p^2*(p-7) = 0

(1/5*5*p^-2*p^2*(p-7))/(9*p-36) = 0

( 1/5*p^-2 )

1/5*p^-2 = 0 // : 1/5

p^-2 = 0

p naleu017Cy do O

( 5*p^2 )

5*p^2 = 0 // : 5

p^2 = 0

p = 0

( p-7 )

p-7 = 0 // + 7

p = 7

p in { 0}

p = 7

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