(1)/(6)(n-12)=(1)/(4)(n+8)

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Solution for (1)/(6)(n-12)=(1)/(4)(n+8) equation: 



(1)/(6)(n-12)=(1)/(4)(n+8)

We move all terms to the left:

(1)/(6)(n-12)-((1)/(4)(n+8))=0



Domain of the equation: 6(n-12)!=0

n∈R





Domain of the equation: 4(n+8))!=0

n∈R



We calculate fractions


(4nn/(6(n-12)*4(n+8)))+(-6nn/(6(n-12)*4(n+8)))=0



We calculate terms in parentheses: +(4nn/(6(n-12)*4(n+8))), so:

4nn/(6(n-12)*4(n+8))

We multiply all the terms by the denominator


4nn

Back to the equation:

+(4nn)





We calculate terms in parentheses: +(-6nn/(6(n-12)*4(n+8))), so:

-6nn/(6(n-12)*4(n+8))

We multiply all the terms by the denominator


-6nn

Back to the equation:

+(-6nn)



We get rid of parentheses

4nn-6nn=0

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