(1)/(a-3)-(1)/(3-a)

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Solution for (1)/(a-3)-(1)/(3-a) equation: 


D( a )

3-a = 0

a-3 = 0

3-a = 0

3-a = 0

3-a = 0 // - 3

-a = -3 // * -1

a = 3

a-3 = 0

a-3 = 0

a-3 = 0 // + 3

a = 3

a in (-oo:3) U (3:+oo)

1/(a-3)-(1/(3-a)) = 0

1/(a-3)-(3-a)^-1 = 0

1/(a-3)-1/(3-a) = 0

(1*(3-a))/((a-3)*(3-a))+(-1*(a-3))/((a-3)*(3-a)) = 0

1*(3-a)-1*(a-3) = 0

6-2*a = 0

(6-2*a)/((a-3)*(3-a)) = 0

(6-2*a)/((a-3)*(3-a)) = 0 // * (a-3)*(3-a)

6-2*a = 0

6-2*a = 0 // - 6

-2*a = -6 // : -2

a = -6/(-2)

a = 3

a in { 3} 

a belongs to the empty set

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