(1)/(r-5)=(7)/(2r)

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Solution for (1)/(r-5)=(7)/(2r) equation: 


D( r )

r-5 = 0

2*r = 0

r-5 = 0

r-5 = 0

r-5 = 0 // + 5

r = 5

2*r = 0

2*r = 0

2*r = 0 // : 2

r = 0

r in (-oo:0) U (0:5) U (5:+oo)

1/(r-5) = 7/(2*r) // - 7/(2*r)

1/(r-5)-(7/(2*r)) = 0

1/(r-5)+(-7/2)*r^-1 = 0

1/(r-5)-7/(2*r) = 0

(1*2*r)/(2*r*(r-5))+(-7*(r-5))/(2*r*(r-5)) = 0

1*2*r-7*(r-5) = 0

35-5*r = 0

(35-5*r)/(2*r*(r-5)) = 0

(35-5*r)/(2*r*(r-5)) = 0 // * 2*r*(r-5)

35-5*r = 0

35-5*r = 0 // - 35

-5*r = -35 // : -5

r = -35/(-5)

r = 7

r = 7

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