(1)/(x)+(2)/(x-3)=3

Solution for (1)/(x)+(2)/(x-3)=3 equation:

(1)/(x)+(2)/(x-3)=3

We move all terms to the left:

(1)/(x)+(2)/(x-3)-(3)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: (x-3)!=0

We move all terms containing x to the left, all other terms to the right

x!=3

x∈R


We calculate fractions


(1*(x-3))/(x^2-3x)+2x/(x^2-3x)-3=0


We calculate terms in parentheses: +(1*(x-3))/(x^2-3x), so:

1*(x-3))/(x^2-3x

We add all the numbers together, and all the variables

-3x+1*(x-3))/(x^2

We multiply all the terms by the denominator


-3x*(x^2+1*(x-3))

Back to the equation:

+(-3x*(x^2+1*(x-3)))


We multiply all the terms by the denominator


((-3x*(x^2+1*(x-3))))*(x^2-3x)+2x-3*(x^2-3x)=0


We calculate terms in parentheses: +((-3x*(x^2+1*(x-3))))*(x^2-3x), so:

(-3x*(x^2+1*(x-3))))*(x^2-3x

We add all the numbers together, and all the variables

-3x+(-3x*(x^2+1*(x-3))))*(x^2

Back to the equation:

+(-3x+(-3x*(x^2+1*(x-3))))*(x^2)


We add all the numbers together, and all the variables

2x+(-3x+(-3x*(x^2+1*(x-3))))*x^2-3*(x^2-3x)=0

We multiply parentheses

-3x^2+2x+(-3x+(-3x*(x^2+1*(x-3))))*x^2+9x=0

We add all the numbers together, and all the variables

-3x^2+11x+(-3x+(-3x*(x^2+1*(x-3))))*x^2=0