(1)/3(6x-5)-x=(1)/3-2(X+1)

Solution for (1)/3(6x-5)-x=(1)/3-2(X+1) equation:

(1)/3(6x-5)-x=(1)/3-2(x+1)

We move all terms to the left:

(1)/3(6x-5)-x-((1)/3-2(x+1))=0


Domain of the equation: 3(6x-5)!=0

x∈R



Domain of the equation: 3-2(x+1))!=0

We move all terms containing x to the left, all other terms to the right

-2(x+1))!=-3

x∈R


We add all the numbers together, and all the variables

-1x+1/3(6x-5)-(1/3-2(x+1))=0

We calculate fractions


-1x+(-2(x+1))+1*3)/52x+(-3x6/52x=0


We calculate terms in parentheses: +(-2(x+1)), so:

-2(x+1)

We multiply parentheses

-2x-2

Back to the equation:

+(-2x-2)


We get rid of parentheses

-1x-2x+1*3)/52x+(-3x6/52x-2=0

We calculate fractions

We do not support expression: x^7