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(1)/y-3=(3)/y-5
We move all terms to the left:
(1)/y-3-((3)/y-5)=0
Domain of the equation: y!=0
y∈R
Domain of the equation: y-5)!=0We get rid of parentheses
y∈R
1/y-3/y+5-3=0
We multiply all the terms by the denominator
5*y-3*y+1-3=0
We add all the numbers together, and all the variables
2y-2=0
We move all terms containing y to the left, all other terms to the right
2y=2
y=2/2
y=1
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