(1+(1/y))/(1+(1/y))

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Solution for (1+(1/y))/(1+(1/y)) equation: 


D( y )

y = 0

1/y+1 = 0

y = 0

y = 0

1/y+1 = 0

1/y+1 = 0

1*y^-1 = -1 // : 1

y^-1 = -1

-1 < 0

1/(y^1) = -1 // * y^1

1 = -1*y^1 // : -1

-1 = y^1

y = -1

y in (-oo:-1) U (-1:0) U (0:+oo)

(1/y+1)/(1/y+1) = 0

1 = 0

y belongs to the empty set

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