(1+2i)(2-3i)=

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Solution for (1+2i)(2-3i)= equation:


Simplifying
(1 + 2i)(2 + -3i) = 0

Multiply (1 + 2i) * (2 + -3i)
(1(2 + -3i) + 2i * (2 + -3i)) = 0
((2 * 1 + -3i * 1) + 2i * (2 + -3i)) = 0
((2 + -3i) + 2i * (2 + -3i)) = 0
(2 + -3i + (2 * 2i + -3i * 2i)) = 0
(2 + -3i + (4i + -6i2)) = 0

Combine like terms: -3i + 4i = 1i
(2 + 1i + -6i2) = 0

Solving
2 + 1i + -6i2 = 0

Solving for variable 'i'.

Factor a trinomial.
(2 + -3i)(1 + 2i) = 0

Subproblem 1

Set the factor '(2 + -3i)' equal to zero and attempt to solve: Simplifying 2 + -3i = 0 Solving 2 + -3i = 0 Move all terms containing i to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -3i = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -3i = 0 + -2 -3i = 0 + -2 Combine like terms: 0 + -2 = -2 -3i = -2 Divide each side by '-3'. i = 0.6666666667 Simplifying i = 0.6666666667

Subproblem 2

Set the factor '(1 + 2i)' equal to zero and attempt to solve: Simplifying 1 + 2i = 0 Solving 1 + 2i = 0 Move all terms containing i to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 2i = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 2i = 0 + -1 2i = 0 + -1 Combine like terms: 0 + -1 = -1 2i = -1 Divide each side by '2'. i = -0.5 Simplifying i = -0.5

Solution

i = {0.6666666667, -0.5}

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