(1+2i)(x+yi)=1+2y

Simple and best practice solution for (1+2i)(x+yi)=1+2y equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for (1+2i)(x+yi)=1+2y equation: 


Simplifying
(1 + 2i)(x + yi) = 1 + 2y

Reorder the terms:
(1 + 2i)(iy + x) = 1 + 2y

Multiply (1 + 2i) * (iy + x)
(1(iy + x) + 2i * (iy + x)) = 1 + 2y
((iy * 1 + x * 1) + 2i * (iy + x)) = 1 + 2y
((1iy + 1x) + 2i * (iy + x)) = 1 + 2y
(1iy + 1x + (iy * 2i + x * 2i)) = 1 + 2y

Reorder the terms:
(1iy + 1x + (2ix + 2i2y)) = 1 + 2y
(1iy + 1x + (2ix + 2i2y)) = 1 + 2y

Reorder the terms:
(2ix + 1iy + 2i2y + 1x) = 1 + 2y
(2ix + 1iy + 2i2y + 1x) = 1 + 2y

Solving
2ix + 1iy + 2i2y + 1x = 1 + 2y

Solving for variable 'i'.

Reorder the terms:
-1 + 2ix + 1iy + 2i2y + 1x + -2y = 1 + 2y + -1 + -2y

Reorder the terms:
-1 + 2ix + 1iy + 2i2y + 1x + -2y = 1 + -1 + 2y + -2y

Combine like terms: 1 + -1 = 0
-1 + 2ix + 1iy + 2i2y + 1x + -2y = 0 + 2y + -2y
-1 + 2ix + 1iy + 2i2y + 1x + -2y = 2y + -2y

Combine like terms: 2y + -2y = 0
-1 + 2ix + 1iy + 2i2y + 1x + -2y = 0

The solution to this equation could not be determined.

See similar equations:

| 4x+3x-5=12 | | 5(4t-9)-4=111 | | 4(x+2)-2(x+3)=12 | | 5(4t-9)-9=111 | | 32m+24=17m+2 | | 4p-2p+4=-1+21 | | 9x-(2x+28)=35 | | (-2+4i)(x+yi)+3(x+yi)=4(2+i) | | 4xy=2x+2y | | 15y+13=2y-5 | | 2(3y+2)=-14 | | -2(3+5a)=-114 | | 4x^2+3=-12 | | (3+4i)(x+yi)=7+26i | | -11(5-11a)+8a=11(-5+5a) | | 5x-4x+9x= | | -2(-7-3)+4(-7)=-(-7+1) | | 3(3x-41)=12 | | 7+35x=28x+8 | | 5x-4+5x=2x+122-6x | | 5xn=16 | | W+34=-34 | | 5(3d-4)=-5(d-2) | | 5(w-1)-(8w-5)=-4w | | 3k^2-16k-12=0 | | 2x-x+3x-2=16 | | -6A+2+7A=8-26 | | 20x-14-11x=8-6x+2 | | (3+7y)8=16 | | .1y+.9=.2-.6y | | 8*y(-4)=18+4y | | -8+y=15 |

Equations solver categories