(1+2i)*z-3-2i=0

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Solution for (1+2i)*z-3-2i=0 equation:


Simplifying
(1 + 2i) * z + -3 + -2i = 0

Reorder the terms for easier multiplication:
z(1 + 2i) + -3 + -2i = 0
(1 * z + 2i * z) + -3 + -2i = 0

Reorder the terms:
(2iz + 1z) + -3 + -2i = 0
(2iz + 1z) + -3 + -2i = 0

Reorder the terms:
-3 + -2i + 2iz + 1z = 0

Solving
-3 + -2i + 2iz + 1z = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + -2i + 2iz + 3 + 1z = 0 + 3

Reorder the terms:
-3 + 3 + -2i + 2iz + 1z = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -2i + 2iz + 1z = 0 + 3
-2i + 2iz + 1z = 0 + 3

Combine like terms: 0 + 3 = 3
-2i + 2iz + 1z = 3

Add '-1z' to each side of the equation.
-2i + 2iz + 1z + -1z = 3 + -1z

Combine like terms: 1z + -1z = 0
-2i + 2iz + 0 = 3 + -1z
-2i + 2iz = 3 + -1z

Reorder the terms:
-3 + -2i + 2iz + z = 3 + -1z + -3 + z

Reorder the terms:
-3 + -2i + 2iz + z = 3 + -3 + -1z + z

Combine like terms: 3 + -3 = 0
-3 + -2i + 2iz + z = 0 + -1z + z
-3 + -2i + 2iz + z = -1z + z

Combine like terms: -1z + z = 0
-3 + -2i + 2iz + z = 0

The solution to this equation could not be determined.

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