(1+2i)+(3-i)=

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Solution for (1+2i)+(3-i)= equation:


Simplifying
(1 + 2i) + (3 + -1i) = 0

Remove parenthesis around (1 + 2i)
1 + 2i + (3 + -1i) = 0

Remove parenthesis around (3 + -1i)
1 + 2i + 3 + -1i = 0

Reorder the terms:
1 + 3 + 2i + -1i = 0

Combine like terms: 1 + 3 = 4
4 + 2i + -1i = 0

Combine like terms: 2i + -1i = 1i
4 + 1i = 0

Solving
4 + 1i = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 1i = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 1i = 0 + -4
1i = 0 + -4

Combine like terms: 0 + -4 = -4
1i = -4

Divide each side by '1'.
i = -4

Simplifying
i = -4

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