(1+2i)z=5

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Solution for (1+2i)z=5 equation:


Simplifying
(1 + 2i) * z = 5

Reorder the terms for easier multiplication:
z(1 + 2i) = 5
(1 * z + 2i * z) = 5

Reorder the terms:
(2iz + 1z) = 5
(2iz + 1z) = 5

Solving
2iz + 1z = 5

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1z' to each side of the equation.
2iz + 1z + -1z = 5 + -1z

Combine like terms: 1z + -1z = 0
2iz + 0 = 5 + -1z
2iz = 5 + -1z

Divide each side by '2z'.
i = 2.5z-1 + -0.5

Simplifying
i = 2.5z-1 + -0.5

Reorder the terms:
i = -0.5 + 2.5z-1

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