(1+3i)(1+3i)=0

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Solution for (1+3i)(1+3i)=0 equation: 



(1+3i)(1+3i)=0

We add all the numbers together, and all the variables

(3i+1)(3i+1)=0

We multiply parentheses ..

(+9i^2+3i+3i+1)=0

We get rid of parentheses

9i^2+3i+3i+1=0

We add all the numbers together, and all the variables

9i^2+6i+1=0

a = 9; b = 6; c = +1;
Δ = b2-4ac
Δ = 62-4·9·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$i=\frac{-b}{2a}=\frac{-6}{18}=-1/3$

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