(1+3x)/(8-9x)=y

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Solution for (1+3x)/(8-9x)=y equation:


D( x )

8-(9*x) = 0

8-(9*x) = 0

8-(9*x) = 0

8-9*x = 0

8-9*x = 0 // - 8

-9*x = -8 // : -9

x = -8/(-9)

x = 8/9

x in (-oo:8/9) U (8/9:+oo)

(3*x+1)/(8-(9*x)) = y // - y

(3*x+1)/(8-(9*x))-y = 0

(3*x+1)/(8-9*x)-y = 0

(3*x+1)/(8-9*x)+(-y*(8-9*x))/(8-9*x) = 0

3*x-y*(8-9*x)+1 = 0

3*x+9*x*y-8*y+1 = 0

(3*x+9*x*y-8*y+1)/(8-9*x) = 0

(3*x+9*x*y-8*y+1)/(8-9*x) = 0 // * 8-9*x

3*x+9*x*y-8*y+1 = 0

9*x*y-8*y+1 = 0 // - 1-8*y

9*x*y = -(1-8*y) // : 9*y

x = (-(1-8*y))/(9*y)

x = (-1/9)*y^-1*(1-8*y)

x = (-1/9)*y^-1*(1-8*y)

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