(1+3y)+18=y-3(1+3y)

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Solution for (1+3y)+18=y-3(1+3y) equation:



(1+3y)+18=y-3(1+3y)
We move all terms to the left:
(1+3y)+18-(y-3(1+3y))=0
We add all the numbers together, and all the variables
(3y+1)-(y-3(3y+1))+18=0
We get rid of parentheses
3y-(y-3(3y+1))+1+18=0
We calculate terms in parentheses: -(y-3(3y+1)), so:
y-3(3y+1)
We multiply parentheses
y-9y-3
We add all the numbers together, and all the variables
-8y-3
Back to the equation:
-(-8y-3)
We add all the numbers together, and all the variables
3y-(-8y-3)+19=0
We get rid of parentheses
3y+8y+3+19=0
We add all the numbers together, and all the variables
11y+22=0
We move all terms containing y to the left, all other terms to the right
11y=-22
y=-22/11
y=-2

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