(1+4x)*(-2)+27=5(x-4)+32x

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Solution for (1+4x)*(-2)+27=5(x-4)+32x equation: 



(1+4x)(-2)+27=5(x-4)+32x

We move all terms to the left:

(1+4x)(-2)+27-(5(x-4)+32x)=0

We add all the numbers together, and all the variables

(4x+1)(-2)-(5(x-4)+32x)+27=0

We multiply parentheses ..

(-8x-2)-(5(x-4)+32x)+27=0



We calculate terms in parentheses: -(5(x-4)+32x), so:

5(x-4)+32x

We add all the numbers together, and all the variables

32x+5(x-4)

We multiply parentheses

32x+5x-20

We add all the numbers together, and all the variables

37x-20

Back to the equation:

-(37x-20)



We get rid of parentheses

-8x-37x-2+20+27=0

We add all the numbers together, and all the variables

-45x+45=0

We move all terms containing x to the left, all other terms to the right

-45x=-45

x=-45/-45

x=1

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