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(1+4x)(1+4x)=0
We add all the numbers together, and all the variables
(4x+1)(4x+1)=0
We multiply parentheses ..
(+16x^2+4x+4x+1)=0
We get rid of parentheses
16x^2+4x+4x+1=0
We add all the numbers together, and all the variables
16x^2+8x+1=0
a = 16; b = 8; c = +1;
Δ = b2-4ac
Δ = 82-4·16·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-8}{32}=-1/4$
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