If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(1+6x)(2x-13)=180
We move all terms to the left:
(1+6x)(2x-13)-(180)=0
We add all the numbers together, and all the variables
(6x+1)(2x-13)-180=0
We multiply parentheses ..
(+12x^2-78x+2x-13)-180=0
We get rid of parentheses
12x^2-78x+2x-13-180=0
We add all the numbers together, and all the variables
12x^2-76x-193=0
a = 12; b = -76; c = -193;
Δ = b2-4ac
Δ = -762-4·12·(-193)
Δ = 15040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{15040}=\sqrt{64*235}=\sqrt{64}*\sqrt{235}=8\sqrt{235}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-76)-8\sqrt{235}}{2*12}=\frac{76-8\sqrt{235}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-76)+8\sqrt{235}}{2*12}=\frac{76+8\sqrt{235}}{24} $
| 12.5-4x=10.5 | | 1/625=1/(5^n) | | 6=3x5 | | x-40/100=160 | | 3+4x5=23 | | 3(2x-1)=3-2x | | 4.2^2x-10.2^x+4=0 | | 10x/12=6 | | (1-x)^5=(2x-1)^5 | | (8^(3x+1)-1)×3=27 | | |3x+2|=|5x−2| | | (7q-46)°+(3q+)°=180° | | x+x=40+180 | | 16=40-8n | | x/3-2x/5=4 | | 6x-3(x-2)=0 | | 2x+3x+7=4x+10 | | 4x-x+5=2x+10 | | 5m-40=60 | | (3x-3)/24=5x/ | | f(Y/X)=2 | | 2^2x-62^x+8=0 | | 8(t-5)+2=(4.8)t+4 | | 2(-5+b)=20 | | 6m-3=49 | | -5(5-x)=50 | | 5x-7=E | | -(-3x-5)+1=-x | | x3x+40=10 | | 1/4(12x+32)+3x=1/3(15x+24) | | 18+y=4,y= | | 4(3x-2)-8=2(6x+8)+3x |