If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(1+8i)(2+8i)=0
We add all the numbers together, and all the variables
(8i+1)(8i+2)=0
We multiply parentheses ..
(+64i^2+16i+8i+2)=0
We get rid of parentheses
64i^2+16i+8i+2=0
We add all the numbers together, and all the variables
64i^2+24i+2=0
a = 64; b = 24; c = +2;
Δ = b2-4ac
Δ = 242-4·64·2
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-8}{2*64}=\frac{-32}{128} =-1/4 $$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+8}{2*64}=\frac{-16}{128} =-1/8 $
| (1+8i)^2=0 | | (2+i)(2+4i)=0 | | 4y-2×=10 | | 2x+2(x+7)=14x–6 | | (-6+3i)(2+8i)=0 | | -i(-15+13i)=0 | | 10(j+5)=80 | | (u+50)/(7)=-4 | | (z)/(-10)+-83=-74 | | (p)/(3)+10=17 | | –33+5f=37 | | 5=(g)/(7)-2 | | 11i(9-6i)=0 | | (k)/(8)+37=47 | | 6h+29=95 | | 3=f+198 | | 19=(z)/(3)+17 | | (p)/(4)-1=3 | | -1/2m÷3=57 | | -6i(-4+6i)=0 | | Y=3x2-4x+7 | | (w)/(-7)+-33=-35 | | -5i-7-(5-6i)=0 | | -20=(w)/(-3)+-17 | | 3+7i-(2-6i)=0 | | 6x−(−8x+5)+3= −9 | | 6x−(−8x+5)+3= −9− | | 6x−(−8x+5)+3=-9 | | 40°=9x-2+20x+5 | | (x+5)*4+x*x=16 | | (x+5)*4+x*x=4 | | 5(x+4)-8=12 |