(1+i)(1-i)=

Solution for (1+i)(1-i)= equation:

Simplifying
(1 + i)(1 + -1i) = 0

Multiply (1 + i) * (1 + -1i)
(1(1 + -1i) + i(1 + -1i)) = 0
((1 * 1 + -1i * 1) + i(1 + -1i)) = 0
((1 + -1i) + i(1 + -1i)) = 0
(1 + -1i + (1 * i + -1i * i)) = 0
(1 + -1i + (1i + -1i2)) = 0

Combine like terms: -1i + 1i = 0
(1 + 0 + -1i2) = 0
(1 + -1i2) = 0

Solving
1 + -1i2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1i2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1i2 = 0 + -1
-1i2 = 0 + -1

Combine like terms: 0 + -1 = -1
-1i2 = -1

Divide each side by '-1'.
i2 = 1

Simplifying
i2 = 1

Take the square root of each side:
i = {-1, 1}