(1+i)(4-3i)=

Solution for (1+i)(4-3i)= equation:

Simplifying
(1 + i)(4 + -3i) = 0

Multiply (1 + i) * (4 + -3i)
(1(4 + -3i) + i(4 + -3i)) = 0
((4 * 1 + -3i * 1) + i(4 + -3i)) = 0
((4 + -3i) + i(4 + -3i)) = 0
(4 + -3i + (4 * i + -3i * i)) = 0
(4 + -3i + (4i + -3i2)) = 0

Combine like terms: -3i + 4i = 1i
(4 + 1i + -3i2) = 0

Solving
4 + 1i + -3i2 = 0

Solving for variable 'i'.

Factor a trinomial.
(4 + -3i)(1 + i) = 0

Subproblem 1
Set the factor '(4 + -3i)' equal to zero and attempt to solve:

Simplifying
4 + -3i = 0

Solving
4 + -3i = 0

Move all terms containing i to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -3i = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -3i = 0 + -4
-3i = 0 + -4

Combine like terms: 0 + -4 = -4
-3i = -4

Divide each side by '-3'.
i = 1.333333333

Simplifying
i = 1.333333333
Subproblem 2
Set the factor '(1 + i)' equal to zero and attempt to solve:

Simplifying
1 + i = 0

Solving
1 + i = 0

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + i = 0 + -1

Combine like terms: 1 + -1 = 0
0 + i = 0 + -1
i = 0 + -1

Combine like terms: 0 + -1 = -1
i = -1

Simplifying
i = -1
Solution
i = {1.333333333, -1}