(1+i)*z+1=0

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Solution for (1+i)*z+1=0 equation:


Simplifying
(1 + i) * z + 1 = 0

Reorder the terms for easier multiplication:
z(1 + i) + 1 = 0
(1 * z + i * z) + 1 = 0

Reorder the terms:
(iz + 1z) + 1 = 0
(iz + 1z) + 1 = 0

Reorder the terms:
1 + iz + 1z = 0

Solving
1 + iz + 1z = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + iz + -1 + 1z = 0 + -1

Reorder the terms:
1 + -1 + iz + 1z = 0 + -1

Combine like terms: 1 + -1 = 0
0 + iz + 1z = 0 + -1
iz + 1z = 0 + -1

Combine like terms: 0 + -1 = -1
iz + 1z = -1

Add '-1z' to each side of the equation.
iz + 1z + -1z = -1 + -1z

Combine like terms: 1z + -1z = 0
iz + 0 = -1 + -1z
iz = -1 + -1z

Divide each side by 'z'.
i = -1z-1 + -1

Simplifying
i = -1z-1 + -1

Reorder the terms:
i = -1 + -1z-1

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