(1+i)2=(-1+i)/(-1+i)

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Solution for (1+i)2=(-1+i)/(-1+i) equation: 


D( i )

i-1 = 0

i-1 = 0

i-1 = 0

i-1 = 0 // + 1

i = 1

i in (-oo:1) U (1:+oo)

(i+1)^2 = (i-1)/(i-1) // - (i-1)/(i-1)

(i+1)^2-((i-1)/(i-1)) = 0

(i+1)^2-1 = 0

(i+1)^2-1 = 0

i^2+2*i = 0

i^2+2*i = 0

i*(i+2) = 0

i+2 = 0 // - 2

i = -2

i*(i+2) = 0

i*(i+2) = 0

( i+2 )

i+2 = 0 // - 2

i = -2

( i )

i = 0

i in { -2, 0 }

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