(1+i)z-2i=4z+1

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Solution for (1+i)z-2i=4z+1 equation:


Simplifying
(1 + i) * z + -2i = 4z + 1

Reorder the terms for easier multiplication:
z(1 + i) + -2i = 4z + 1
(1 * z + i * z) + -2i = 4z + 1

Reorder the terms:
(iz + 1z) + -2i = 4z + 1
(iz + 1z) + -2i = 4z + 1

Reorder the terms:
-2i + iz + 1z = 4z + 1

Reorder the terms:
-2i + iz + 1z = 1 + 4z

Solving
-2i + iz + 1z = 1 + 4z

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1z' to each side of the equation.
-2i + iz + 1z + -1z = 1 + 4z + -1z

Combine like terms: 1z + -1z = 0
-2i + iz + 0 = 1 + 4z + -1z
-2i + iz = 1 + 4z + -1z

Combine like terms: 4z + -1z = 3z
-2i + iz = 1 + 3z

Reorder the terms:
-1 + -2i + iz + -3z = 1 + 3z + -1 + -3z

Reorder the terms:
-1 + -2i + iz + -3z = 1 + -1 + 3z + -3z

Combine like terms: 1 + -1 = 0
-1 + -2i + iz + -3z = 0 + 3z + -3z
-1 + -2i + iz + -3z = 3z + -3z

Combine like terms: 3z + -3z = 0
-1 + -2i + iz + -3z = 0

The solution to this equation could not be determined.

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