(1+i)z-w=2i

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Solution for (1+i)z-w=2i equation:


Simplifying
(1 + i) * z + -1w = 2i

Reorder the terms for easier multiplication:
z(1 + i) + -1w = 2i
(1 * z + i * z) + -1w = 2i

Reorder the terms:
(iz + 1z) + -1w = 2i
(iz + 1z) + -1w = 2i

Reorder the terms:
iz + -1w + 1z = 2i

Solving
iz + -1w + 1z = 2i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-2i' to each side of the equation.
iz + -1w + -2i + 1z = 2i + -2i

Reorder the terms:
-2i + iz + -1w + 1z = 2i + -2i

Combine like terms: 2i + -2i = 0
-2i + iz + -1w + 1z = 0

Add 'w' to each side of the equation.
-2i + iz + -1w + w + 1z = 0 + w

Combine like terms: -1w + w = 0
-2i + iz + 0 + 1z = 0 + w
-2i + iz + 1z = 0 + w
Remove the zero:
-2i + iz + 1z = w

Add '-1z' to each side of the equation.
-2i + iz + 1z + -1z = w + -1z

Combine like terms: 1z + -1z = 0
-2i + iz + 0 = w + -1z
-2i + iz = w + -1z

Reorder the terms:
-2i + iz + -1w + z = w + -1w + -1z + z

Combine like terms: w + -1w = 0
-2i + iz + -1w + z = 0 + -1z + z
-2i + iz + -1w + z = -1z + z

Combine like terms: -1z + z = 0
-2i + iz + -1w + z = 0

The solution to this equation could not be determined.

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