(1+u)(5u-3)=0

Solution for (1+u)(5u-3)=0 equation:

(1+u)(5u-3)=0

We add all the numbers together, and all the variables

(u+1)(5u-3)=0

We multiply parentheses ..

(+5u^2-3u+5u-3)=0

We get rid of parentheses

5u^2-3u+5u-3=0

We add all the numbers together, and all the variables

5u^2+2u-3=0

a = 5; b = 2; c = -3;
Δ = b2-4ac
Δ = 22-4·5·(-3)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-8}{2*5}=\frac{-10}{10}
=-1
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+8}{2*5}=\frac{6}{10}
=3/5
$