(1+u)(5u-3)=0

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Solution for (1+u)(5u-3)=0 equation:



(1+u)(5u-3)=0
We add all the numbers together, and all the variables
(u+1)(5u-3)=0
We multiply parentheses ..
(+5u^2-3u+5u-3)=0
We get rid of parentheses
5u^2-3u+5u-3=0
We add all the numbers together, and all the variables
5u^2+2u-3=0
a = 5; b = 2; c = -3;
Δ = b2-4ac
Δ = 22-4·5·(-3)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-8}{2*5}=\frac{-10}{10} =-1 $
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+8}{2*5}=\frac{6}{10} =3/5 $

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