(1+v)(2v-3)=0

Solution for (1+v)(2v-3)=0 equation:

Simplifying
(1 + v)(2v + -3) = 0

Reorder the terms:
(1 + v)(-3 + 2v) = 0

Multiply (1 + v) * (-3 + 2v)
(1(-3 + 2v) + v(-3 + 2v)) = 0
((-3 * 1 + 2v * 1) + v(-3 + 2v)) = 0
((-3 + 2v) + v(-3 + 2v)) = 0
(-3 + 2v + (-3 * v + 2v * v)) = 0
(-3 + 2v + (-3v + 2v2)) = 0

Combine like terms: 2v + -3v = -1v
(-3 + -1v + 2v2) = 0

Solving
-3 + -1v + 2v2 = 0

Solving for variable 'v'.

Factor a trinomial.
(-1 + -1v)(3 + -2v) = 0

Subproblem 1
Set the factor '(-1 + -1v)' equal to zero and attempt to solve:

Simplifying
-1 + -1v = 0

Solving
-1 + -1v = 0

Move all terms containing v to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1v = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1v = 0 + 1
-1v = 0 + 1

Combine like terms: 0 + 1 = 1
-1v = 1

Divide each side by '-1'.
v = -1

Simplifying
v = -1
Subproblem 2
Set the factor '(3 + -2v)' equal to zero and attempt to solve:

Simplifying
3 + -2v = 0

Solving
3 + -2v = 0

Move all terms containing v to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -2v = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -2v = 0 + -3
-2v = 0 + -3

Combine like terms: 0 + -3 = -3
-2v = -3

Divide each side by '-2'.
v = 1.5

Simplifying
v = 1.5
Solution
v = {-1, 1.5}