(1+v)(2v-7)=0

Solution for (1+v)(2v-7)=0 equation:

(1+v)(2v-7)=0

We add all the numbers together, and all the variables

(v+1)(2v-7)=0

We multiply parentheses ..

(+2v^2-7v+2v-7)=0

We get rid of parentheses

2v^2-7v+2v-7=0

We add all the numbers together, and all the variables

2v^2-5v-7=0

a = 2; b = -5; c = -7;
Δ = b2-4ac
Δ = -52-4·2·(-7)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-9}{2*2}=\frac{-4}{4}
=-1
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+9}{2*2}=\frac{14}{4}
=3+1/2
$