(1+x)(2+x)3+x)-(1-x)(2-x)(3-x)=2(x*x*x+1*2*3)

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Solution for (1+x)(2+x)3+x)-(1-x)(2-x)(3-x)=2(x*x*x+1*2*3) equation: 



(1+x)(2+x)3+x)-(1-x)(2-x)(3-x)=2(x*x*x+1*2*3)

We move all terms to the left:

(1+x)(2+x)3+x)-(1-x)(2-x)(3-x)-(2(x*x*x+1*2*3))=0

We add all the numbers together, and all the variables

(x+1)(x+2)3+x)-(-1x-1x-1x+3)-(2(x*x*x+6))+1)(+2)(=0

We add all the numbers together, and all the variables

-3x+(x+1)(x+2)3+x)-(+3)-(2(x*x*x+6))+1)(+2)(=0

We multiply parentheses ..

(+x^2+2x+x+2)3-3x+x)-(+3)-(2(x*x*x+6))+1)(+2)(=0

We add all the numbers together, and all the variables

(+x^2+2x+x+2)3-3x+x)-3-(2(x*x*x+6))+1)2(=0

We multiply parentheses

3x^2+6x+3x-3x+x)-3-(2(x*x*x+6))+1)2(+6=0

We add all the numbers together, and all the variables

3x^2+6x+x)-3-(2(x*x*x+6))+1)2(+6=0

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