(1+x)+3x=-2(x+1)

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Solution for (1+x)+3x=-2(x+1) equation: 



(1+x)+3x=-2(x+1)

We move all terms to the left:

(1+x)+3x-(-2(x+1))=0

We add all the numbers together, and all the variables

(x+1)+3x-(-2(x+1))=0

We add all the numbers together, and all the variables

3x+(x+1)-(-2(x+1))=0

We get rid of parentheses

3x+x-(-2(x+1))+1=0



We calculate terms in parentheses: -(-2(x+1)), so:

-2(x+1)

We multiply parentheses

-2x-2

Back to the equation:

-(-2x-2)



We add all the numbers together, and all the variables

4x-(-2x-2)+1=0

We get rid of parentheses

4x+2x+2+1=0

We add all the numbers together, and all the variables

6x+3=0

We move all terms containing x to the left, all other terms to the right

6x=-3

x=-3/6

x=-1/2

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