(1+y)(2y-5)=0

Solution for (1+y)(2y-5)=0 equation:

Simplifying
(1 + y)(2y + -5) = 0

Reorder the terms:
(1 + y)(-5 + 2y) = 0

Multiply (1 + y) * (-5 + 2y)
(1(-5 + 2y) + y(-5 + 2y)) = 0
((-5 * 1 + 2y * 1) + y(-5 + 2y)) = 0
((-5 + 2y) + y(-5 + 2y)) = 0
(-5 + 2y + (-5 * y + 2y * y)) = 0
(-5 + 2y + (-5y + 2y2)) = 0

Combine like terms: 2y + -5y = -3y
(-5 + -3y + 2y2) = 0

Solving
-5 + -3y + 2y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-1 + -1y)(5 + -2y) = 0

Subproblem 1
Set the factor '(-1 + -1y)' equal to zero and attempt to solve:

Simplifying
-1 + -1y = 0

Solving
-1 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1y = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1y = 0 + 1
-1y = 0 + 1

Combine like terms: 0 + 1 = 1
-1y = 1

Divide each side by '-1'.
y = -1

Simplifying
y = -1
Subproblem 2
Set the factor '(5 + -2y)' equal to zero and attempt to solve:

Simplifying
5 + -2y = 0

Solving
5 + -2y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -5 + -2y = 0 + -5

Combine like terms: 5 + -5 = 0
0 + -2y = 0 + -5
-2y = 0 + -5

Combine like terms: 0 + -5 = -5
-2y = -5

Divide each side by '-2'.
y = 2.5

Simplifying
y = 2.5
Solution
y = {-1, 2.5}