(1+y)(3y+2)=0

Solution for (1+y)(3y+2)=0 equation:

Simplifying
(1 + y)(3y + 2) = 0

Reorder the terms:
(1 + y)(2 + 3y) = 0

Multiply (1 + y) * (2 + 3y)
(1(2 + 3y) + y(2 + 3y)) = 0
((2 * 1 + 3y * 1) + y(2 + 3y)) = 0
((2 + 3y) + y(2 + 3y)) = 0
(2 + 3y + (2 * y + 3y * y)) = 0
(2 + 3y + (2y + 3y2)) = 0

Combine like terms: 3y + 2y = 5y
(2 + 5y + 3y2) = 0

Solving
2 + 5y + 3y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(1 + y)(2 + 3y) = 0

Subproblem 1
Set the factor '(1 + y)' equal to zero and attempt to solve:

Simplifying
1 + y = 0

Solving
1 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + y = 0 + -1
y = 0 + -1

Combine like terms: 0 + -1 = -1
y = -1

Simplifying
y = -1
Subproblem 2
Set the factor '(2 + 3y)' equal to zero and attempt to solve:

Simplifying
2 + 3y = 0

Solving
2 + 3y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + 3y = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 3y = 0 + -2
3y = 0 + -2

Combine like terms: 0 + -2 = -2
3y = -2

Divide each side by '3'.
y = -0.6666666667

Simplifying
y = -0.6666666667
Solution
y = {-1, -0.6666666667}