(1+y)(5y-5)=0

Solution for (1+y)(5y-5)=0 equation:

Simplifying
(1 + y)(5y + -5) = 0

Reorder the terms:
(1 + y)(-5 + 5y) = 0

Multiply (1 + y) * (-5 + 5y)
(1(-5 + 5y) + y(-5 + 5y)) = 0
((-5 * 1 + 5y * 1) + y(-5 + 5y)) = 0
((-5 + 5y) + y(-5 + 5y)) = 0
(-5 + 5y + (-5 * y + 5y * y)) = 0
(-5 + 5y + (-5y + 5y2)) = 0

Combine like terms: 5y + -5y = 0
(-5 + 0 + 5y2) = 0
(-5 + 5y2) = 0

Solving
-5 + 5y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 5y2 = 0 + 5

Combine like terms: -5 + 5 = 0
0 + 5y2 = 0 + 5
5y2 = 0 + 5

Combine like terms: 0 + 5 = 5
5y2 = 5

Divide each side by '5'.
y2 = 1

Simplifying
y2 = 1

Take the square root of each side:
y = {-1, 1}