(1+z)(2z+3)=0

Solution for (1+z)(2z+3)=0 equation:

Simplifying
(1 + z)(2z + 3) = 0

Reorder the terms:
(1 + z)(3 + 2z) = 0

Multiply (1 + z) * (3 + 2z)
(1(3 + 2z) + z(3 + 2z)) = 0
((3 * 1 + 2z * 1) + z(3 + 2z)) = 0
((3 + 2z) + z(3 + 2z)) = 0
(3 + 2z + (3 * z + 2z * z)) = 0
(3 + 2z + (3z + 2z2)) = 0

Combine like terms: 2z + 3z = 5z
(3 + 5z + 2z2) = 0

Solving
3 + 5z + 2z2 = 0

Solving for variable 'z'.

Factor a trinomial.
(3 + 2z)(1 + z) = 0

Subproblem 1
Set the factor '(3 + 2z)' equal to zero and attempt to solve:

Simplifying
3 + 2z = 0

Solving
3 + 2z = 0

Move all terms containing z to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 2z = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 2z = 0 + -3
2z = 0 + -3

Combine like terms: 0 + -3 = -3
2z = -3

Divide each side by '2'.
z = -1.5

Simplifying
z = -1.5
Subproblem 2
Set the factor '(1 + z)' equal to zero and attempt to solve:

Simplifying
1 + z = 0

Solving
1 + z = 0

Move all terms containing z to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + z = 0 + -1

Combine like terms: 1 + -1 = 0
0 + z = 0 + -1
z = 0 + -1

Combine like terms: 0 + -1 = -1
z = -1

Simplifying
z = -1
Solution
z = {-1.5, -1}