(1+z)-3i(2-z)=iz+1

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Solution for (1+z)-3i(2-z)=iz+1 equation:


Simplifying
(1 + z) + -3i(2 + -1z) = iz + 1

Remove parenthesis around (1 + z)
1 + z + -3i(2 + -1z) = iz + 1
1 + z + (2 * -3i + -1z * -3i) = iz + 1
1 + z + (-6i + 3iz) = iz + 1

Reorder the terms:
1 + -6i + 3iz + z = iz + 1

Reorder the terms:
1 + -6i + 3iz + z = 1 + iz

Add '-1' to each side of the equation.
1 + -6i + 3iz + -1 + z = 1 + -1 + iz

Reorder the terms:
1 + -1 + -6i + 3iz + z = 1 + -1 + iz

Combine like terms: 1 + -1 = 0
0 + -6i + 3iz + z = 1 + -1 + iz
-6i + 3iz + z = 1 + -1 + iz

Combine like terms: 1 + -1 = 0
-6i + 3iz + z = 0 + iz
-6i + 3iz + z = iz

Solving
-6i + 3iz + z = iz

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1iz' to each side of the equation.
-6i + 3iz + -1iz + z = iz + -1iz

Combine like terms: 3iz + -1iz = 2iz
-6i + 2iz + z = iz + -1iz

Combine like terms: iz + -1iz = 0
-6i + 2iz + z = 0

Add '-1z' to each side of the equation.
-6i + 2iz + z + -1z = 0 + -1z

Combine like terms: z + -1z = 0
-6i + 2iz + 0 = 0 + -1z
-6i + 2iz = 0 + -1z
Remove the zero:
-6i + 2iz = -1z

Combine like terms: -1z + z = 0
-6i + 2iz + z = 0

The solution to this equation could not be determined.

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